A circle has a diameter with endpoints of (-2, 8) and (6, 4). what is the center of the circle?

What is the equation of a circle having a diameter with endpoints?, (x−h)2+(y−k)2=r2 ( x – h ) 2 + ( y – k ) 2 = r 2 is the equation form for a circle with r radius and (h,k) as the center point.

Furthermore, How do you find the area of a circle with endpoints?, A = r^2 * pi where A is the area, and r is the radius of the circle.

Finally,  How do you find the area of a circle using points?, The area of a circle is pi times the radius squared (A = π r²).

Frequently Asked Question:

From the definition of a midpoint, we know that the distance from A to M must be the same as that from M to B . … The endpoint of a line segment going from A = (x₁, y₁) to a midpoint at M = (x, y) is the point B = (2x – x₁, 2y – y₁) .

2 Answers By Expert Tutors. First, since you know the diameter endpoints, you can determine the center of the circle, which is the midpoint between those two points. So the equation of the circle will have the form (x-3)2+(y-5)2=R2 where R is the radius of the circle.

The diameter of a circle is any straight line segment that passes through the center of the circle and whose endpoints are on the circumference of the circle. … The center point of the circle is the center of the diameter, which is the midpoint between (−2,4) and (4,8) .

The distance from a circle’s center to a point on the circle is called the radius of the circle. A radius is a line segment with one endpoint at the center of the circle and the other endpoint on the circle.

From the definition of a midpoint, we know that the distance from A to M must be the same as that from M to B . … The endpoint of a line segment going from A = (x₁, y₁) to a midpoint at M = (x, y) is the point B = (2x – x₁, 2y – y₁) .

How do I find the diameter from the circumference?

  1. Divide the circumference by π, or 3.14 for an estimation.
  2. And that’s it; you have the circle’s diameter.

The standard form equation of a circle with radius r is: (x−h)^2+(y−k)^2=r^2, where r is the radius, h and k are the coordinates of the center of the circle C(h, k). The center of the circle is the midpoint of the line segment making the diameter AB, where A(2,3) and B(2,9).

The standard form of a circle’s equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius. To convert an equation to standard form, you can always complete the square separately in x and y.

more … Any of the two furthest points on a line segment. (Or generally any of the furthest points on anything.)

Endpoints are the points on either end of a line segment or on one end of a ray. The midpoint of a line segment is the point that lies halfway between the endpoints.

A node of a graph of degree 1 (left figure; Harary 1994, p. 15), or, a point at the boundary of line segment or closed interval (right figure).

C = pi * d calculates the circumference (distance around the outside of the circle). D in the formula refers to the diameter which is the width of the circle. The formula for the area of a circle is A = pi * r * r where r is the radius (diameter / 2).

Circle Touching 3 Points

  1. Join up the points to form two lines.
  2. Construct the perpendicular bisector of one line.
  3. Construct the perpendicular bisector of the other line.
  4. Where they cross is the center of the circle.
  5. Place compass on the center point, adjust its length to reach any point, and draw your circle!

The area of a circle is pi times the radius squared (A = π r²).

From the definition of a midpoint, we know that the distance from A to M must be the same as that from M to B . … The endpoint of a line segment going from A = (x₁, y₁) to a midpoint at M = (x, y) is the point B = (2x – x₁, 2y – y₁) .

2 Answers By Expert Tutors. First, since you know the diameter endpoints, you can determine the center of the circle, which is the midpoint between those two points. So the equation of the circle will have the form (x-3)2+(y-5)2=R2 where R is the radius of the circle.

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Kinnedy J.

asked • 01/21/21

1 Expert Answer

general equation for a circle is

(x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center and r = radius

if (-2,-4) and (6,8) are the endpoints of the circle's diameter, their midpoint is the circle's center = (2,2)

average -2 and 6 = 4/2 = 2 and average of 8 and -4 = 4/2 = 2

the radius square = (-2-6)^2 + (-4-8)^2 = 64+ 144 = 208

the circle's equation is

(x-2)^2 + (y-2)^2 = 208

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