Recommended textbooks for you
A First Course in Probability (10th Edition)
ISBN:9780134753119
Author:Sheldon Ross
Publisher:PEARSON
A First Course in Probability
ISBN:9780321794772
Author:Sheldon Ross
Publisher:PEARSON
Dear Student, 1) If there is no restriction then the total arrangements is given by 7!= 5040 . 2)If three Particular books are to be together we make one packet of those three books, and thus the packet along with remaining 4 books can be arranged in 5! ways= 120 , and within the packet the three books can be arranged in 3!=6 ways so total number of such arrangements= 120x6= 720 3) If 2 particular books to occupy end places, this can happen in 2! ways=2 ways, then rest of the 5 books can be arranged in 5! ways=120 ways, so total number of such arrangements are 2x120=240 ways Hope this clears your doubt
With regards
1) If any arrangement is possible, there are 7! = 5040
So there are 5040 ways to arrange 7 books on a shelf.
2) If 3 particular books must always stand together, the 3 books can occupy the following positions on the shelf:
BBB---- -BBB--- --BBB-- ---BBB-
----BBB
For each of these five cases, there are 3! permutations of the 3 books and 4! permutations of the other 4 books,
so the total number of allowed arrangements is 5 x 3!4! = 720.
Open in App
Suggest Corrections
4
Q.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together?
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
Evaluate
(a) 5!
(b) 2! + 1! + 0!
(c) 5P3
Find the number of permutations of the letters of the words
(a) MILK (b) WORLD
If nP4 = 12 nP2 the find n.
Find r if : (a) 13Pr = 156 (b) 8Pr = 336
How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers?
Q.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together?
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
Evaluate
(a) 5!
(b) 2! + 1! + 0!
(c) 5P3
Find the number of permutations of the letters of the words
(a) MILK (b) WORLD
If nP4 = 12 nP2 the find n.
Find r if : (a) 13Pr = 156 (b) 8Pr = 336
How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers?
Q.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together?
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
Evaluate
(a) 5!
(b) 2! + 1! + 0!
(c) 5P3
Find the number of permutations of the letters of the words
(a) MILK (b) WORLD
If nP4 = 12 nP2 the find n.
Find r if : (a) 13Pr = 156 (b) 8Pr = 336
How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers?
Q.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together?
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
Evaluate
(a) 5!
(b) 2! + 1! + 0!
(c) 5P3
Find the number of permutations of the letters of the words
(a) MILK (b) WORLD
If nP4 = 12 nP2 the find n.
Find r if : (a) 13Pr = 156 (b) 8Pr = 336
How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers?
Q.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together?
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
We need to find the number of ways in which 7 different books can be arranged in a shelf.
We also need to arrange three particular books so that they are always together.
For this, we assume the three books as one book for the time being.
Now, we have 5 books. These books can be arranged in
The three books can be arranged in 3 × 2 = 6 ways among themselves.
Thus, the required number of ways is 120 × 6 = 720.
Evaluate
(a) 5!
(b) 2! + 1! + 0!
(c) 5P3
Find the number of permutations of the letters of the words
(a) MILK (b) WORLD
If nP4 = 12 nP2 the find n.
Find r if : (a) 13Pr = 156 (b) 8Pr = 336
How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers?