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Formula used:
tanθ = Perpendicular/Base
tan60° = √3
Calculation:
Let AB be the pole and BC be its shadow.
Let the length of shadow be x and the length of the pole be √3x.
Now, in ΔABC, let θ be the angle of elevation of the sun
⇒ tanθ = AB/BC
⇒ tanθ = √3x/x = √3
⇒ θ = 60°
∴ The angle of elevation of the sun at the time of shadow is 60°.
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If the height of a vertical pole is √3 times the length of its shadow on the ground then the angle of elevation of the sun at that time is a 30∘ b 45∘ c 60∘ d 75∘
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