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8
A metallic right circular cone 20 cm high and whose vertical angle is 60° is cut into two parts at the middle of its height by a plane parallel to its base. If the frustum so obtained be drawn into a wire of diameter
In fig. cone ABC is cut out by a plane parallel to the base FG. DEFG is the frustum so obtained. Let O be the centre of the base of the cone and O’ the centre of the base of the frustum.
It is given that ∠BAC = 60° ∠OAC = 30°
In right triangle AOC, tan
And, C =
Height of the frustum = P'O =
volume of the frustum =
Radius of the wire =
Volume of wire =