A letter of english alphabet is chosen at random what is the probability that the letter is a vowel

The sample space for all 3 problems contains 26 equally likely choices: {a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z} 1. vowel Set of successful letters contains 5 equally likely choices from the sample space: {a,e,i,o,u} That's 5 out of 26 or a probability of 5/26 2. precedes m and is a vowel Set of successful letters contains 3 equally likely choices from the sample space: {a,e,i} That's 3 out of 26 or a probability of 3/26. 2. succeeds n and is a vowel Set of successful letters contains 2 equally likely choices from the sample space: {o,u} That's 2 out of 26 or a probability of 2/26, which reduces to 1/13. Edwin

Solution:

Given, a letter of English alphabets is chosen at random.

We have to determine the probability that the letter is a consonant.

There are 26 English alphabets which consist of 5 vowels and 21 consonants.

The probability of selecting a letter that is a consonant is given by

Favourable outcomes = b, c, d, f, g, h , j, k , l, m, n, p, q, r, s, t, v, w, x, y, z

Number of favourable outcomes = 21

Number of possible outcomes = 26

Probability = number of favourable outcomes / number of possible outcomes

Probability = 21/26

Therefore, the probability of choosing an alphabet that is a consonant is 21/26.

✦ Try This: A letter of English alphabets is chosen at random. Determine the probability that the letter is a vowel.