Recommended textbooks for you  A First Course in Probability (10th Edition) ISBN:9780134753119 Author:Sheldon Ross Publisher:PEARSON A First Course in Probability ISBN:9780321794772 Author:Sheldon Ross Publisher:PEARSON
Dear Student, 1) If there is no restriction then the total arrangements is given by 7!= 5040 . 2)If three Particular books are to be together we make one packet of those three books, and thus the packet along with remaining 4 books can be arranged in 5! ways= 120 , and within the packet the three books can be arranged in 3!=6 ways so total number of such arrangements= 120x6= 720 3) If 2 particular books to occupy end places, this can happen in 2! ways=2 ways, then rest of the 5 books can be arranged in 5! ways=120 ways, so total number of such arrangements are 2x120=240 ways Hope this clears your doubt With regards 1) If any arrangement is possible, there are 7! = 5040 2) If 3 particular books must always stand together, the 3 books can occupy the following positions on the shelf: BBB---- -BBB--- --BBB-- ---BBB- ----BBB For each of these five cases, there are 3! permutations of the 3 books and 4! permutations of the other 4 books, Open in App Suggest Corrections 4 Q. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together? We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. Evaluate (a) 5! (b) 2! + 1! + 0! (c) 5P3 Find the number of permutations of the letters of the words (a) MILK (b) WORLD If nP4 = 12 nP2 the find n. Find r if : (a) 13Pr = 156 (b) 8Pr = 336 How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers? Q. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together? We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. Evaluate (a) 5! (b) 2! + 1! + 0! (c) 5P3 Find the number of permutations of the letters of the words (a) MILK (b) WORLD If nP4 = 12 nP2 the find n. Find r if : (a) 13Pr = 156 (b) 8Pr = 336 How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers? Q. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together? We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. Evaluate (a) 5! (b) 2! + 1! + 0! (c) 5P3 Find the number of permutations of the letters of the words (a) MILK (b) WORLD If nP4 = 12 nP2 the find n. Find r if : (a) 13Pr = 156 (b) 8Pr = 336 How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers? Q. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together? We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. Evaluate (a) 5! (b) 2! + 1! + 0! (c) 5P3 Find the number of permutations of the letters of the words (a) MILK (b) WORLD If nP4 = 12 nP2 the find n. Find r if : (a) 13Pr = 156 (b) 8Pr = 336 How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers? Q. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. In how many ways can 7 different books be arranged in a shelf? In how many ways can we arrange three particulars books so that they are always together? We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. We need to find the number of ways in which 7 different books can be arranged in a shelf. We also need to arrange three particular books so that they are always together. For this, we assume the three books as one book for the time being. Now, we have 5 books. These books can be arranged in The three books can be arranged in 3 × 2 = 6 ways among themselves. Thus, the required number of ways is 120 × 6 = 720. Evaluate (a) 5! (b) 2! + 1! + 0! (c) 5P3 Find the number of permutations of the letters of the words (a) MILK (b) WORLD If nP4 = 12 nP2 the find n. Find r if : (a) 13Pr = 156 (b) 8Pr = 336 How many 3 digit numbers can be formed using the digit 2, 3, 4, 5 and 6 without repetitions? How many of these are even numbers? |
How many ways can 7 books be arranged on a shelf if 1/3 particular books always stand together ii two particular books must occupy the?
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