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A man carrying a bag of mass 25 kg climbs up to a height of 10 m in 5 seconds. Calculate the power delivered by him to the bag. Your browser is no longer supported. Update it to get the best YouTube experience and our latest features. Learn more PhysicsGiven, Mass = 20 kg (a) As there is no displacement of the man, so work done is Zero. (b) We know, Work done = Kinetic energy of man = 1 / 2 × mass × (velocity)2 Work done=Kinetic energy of man=12×mass×velocity2=12×20×32=12×20×9=90J\text{Work done} = \text{Kinetic energy of man} \\[0.5em] = \dfrac{1}{2} \times \text{mass} \times \text{velocity}^2 \\[0.5em] = \dfrac{1}{2} \times 20 \times 3^2 \\[0.5em] = \dfrac{1}{2} \times 20 \times 9 \\[0.5em] = 90 J \\[0.5em]Work done=Kinetic energy of man=21×mass×velocity2=21×20×32=21×20×9=90J ∴ Energy Gained = 90 J (c) We know, Potential energy = mgh PE=20×10×0.5⇒U=100J\text{PE} = 20 \times 10 \times 0.5 \\[0.5em] \Rightarrow U = 100 J \\[0.5em]PE=20×10×0.5⇒U=100J How much energy is gained by a box of mass 20 kg when a man Mass of box = 20 kg Zero work is done as there is no displacement of the man. Is there an error in this question or solution? |
How much energy is given by a box of mass 20kg when a man carrying the box waits for 5 minutes for a bus?
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