Last updated at June 11, 2021 by Teachoo
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According to the question, reflected angle is at an angle of 90° to incident ray ∴ ∠AOB = 90° ∠i + ∠r = 90° …(1) According to the law of reflection, Angle of incidence = Angle of reflection ∠i = ∠r Putting ∠i = ∠r in equation (1) ∠i + ∠i = 90° 2 ∠i = 90° ∠i = 90/2 ∠i = 45° ∴ Angle of incidence = 45° What is the angle of incidence of a ray if the reflected ray is at an angle of 90° to the incident ray? If the reflected ray is at an angle of 90° to the incident ray, then the angle of incidence is 45 °. According to the law of reflection, the angle of incidence is equal to the angle of reflection. Therefore, the angle of incidence and the angle of reflection both are `90^@/2 = 45^@` Concept: Law of Reflection of Light Is there an error in this question or solution? Open in App Suggest Corrections 21 |