What is the de-Broglie wavelength of the electron accelerated through a potential difference of 100 volt?

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Text Solution

Solution : Here, `V=100` Volts.The de- Broglie wavelength `lambda " is " lambda =(1.227)/(sqrt(V))nm`. <br> `=(1.227)/(sqrt(100))=(1.227)/(10) =0.1227=0.123 nm`. <br> The value of de Broglie wavelength is associated with the wavelength of X-ray.