What is the least number which when divided by 4 6 8 12 and 16 leaves a remainder of 2 in each case?

The least number which when divided by 4, 6, 8, 12 and 16 leaves a remainder of 2 in each case is : [A]46 [B]48 [C]50 [D]56

50 Because LCM of 4, 6, 8, 12 and 16 is 48 ∴ Required number = 48 + 2 = 50

Hence option [C] is correct answer.