You're dealing with a double replacement reaction in which two soluble ionic compounds react to form an insoluble solid that precipitates out of the aqueous solution. In your case, sodium hydroxide, #"NaOH"#, and copper(II) nitrate, #"Cu"("NO"_3)_2#, will dissociate completely in aqueous solution to form cations and anions
The reaction will produce copper(II) hydroxide, #"Cu"("OH")_2#, an insoluble ionic compound that precipitates out of solution, and aqueous sodium nitrate, #"NaNO"_3#, another soluble ionic compound. The balanced chemical equation for this reaction would look like this
Now, notice that you need #2# moles of sodium hydroxide for every #1# mole of copper(II) nitrate that takes part in the reaction. To get the complete ionic equation, rewrite the soluble ionic compounds as cations and anions
This is equivalent to
Now, in order to get the net ionic equation, you must eliminate spectator ions, i.e. ions that are present on both sides of the equation In this case, you would have
which is equivalent to
Copper(II) hydroxide is a blue insoluble solid that precipitates out of solution.
CuSO4 + NaOH → Cu(OH)2 + Na2SO4 Word equation: Copper (II) Sulfate plus Sodium Hydroxide → Copper (II) hydroxide + Sodium sulfate Type of Chemical Reaction: For this reaction we have a double replacement reaction. Balancing Strategies: To balance this reaction be sure to count all of the oxygen atoms on both sides of the equation.
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