What is the probability of getting a spade or a heart

there are 2 hearts in every number and as well as the spades

Notice that there are 52 cards then the half of it is 26 , hearts and spades are 13.

Probability

• favourable outcomes / possible outcomes

P = 13/52

= 1/4

ANSWER

• 1/4 is the probability that the card shows a heart or a spade

Answer:

The probability of choosing a heart, P(Heart) = 13/52 = 0.25. Without replacement, you now have 51 cards left in the deck. So the probability of subsequently choosing a Spade is, P(Spade) = 13/51.

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What is the probability of drawing a heart and then a spade in 2 successive draws from a standard deck of cards? Do we consider these as independent events thus yielding:

$$\Pr(\text{Spade and Heart})=\Pr(\text{Spade})\times\Pr(\text{Heart})\rightarrow\frac{13}{52}\times\frac{13}{52}$$

or conditional so that:

$$\Pr(\text{Spade then Heart})=\Pr(\text{Spade})\times\Pr(\text{Heart})\rightarrow\frac{13}{52}\times\frac{13}{51}$$