What least number must be subtracted from 13601 to get a number exactly divisible by 87? Show First, we will divide 13601 by 87. Remainder = 29So, 29 must be subtracted from 13601 to get a number exactly divisible by 87.i.e., 13601 − 29 = 13572 Now, we have: ∴ 29 must be subtracted from 13601 to make it divisible by 87. Concept: Concept for Whole Numbers Is there an error in this question or solution? Page 2What least number must be added to 1056 to get a number exactly divisible by 23? First, we will divide 1056 by 23. Required number = 23 − 21 = 2So, 2 must be added to 1056 to make it exactly divisible by 23.i.e., 1056 + 2 = 1058 Now, we have: ∴ 1058 is exactly divisible by 23. Concept: Concept for Whole Numbers Is there an error in this question or solution? Page 3We have to find the largest four digit number divisible by 16 .The largest four-digit number = 9999Therefore, dividend =9999 Divisor =16 Here, we get remainder =15Therefore, 15 must be subtracted from 9999 to get the largest four digit number that is divisible by 16.i.e., 9999 − 15 = 9984 Thus, 9984 is the largest four-digit number that is divisible by 16.
Discussion :: Numbers - General Questions (Q.No.50)
Sathya said: (Mon, Jul 11, 2016 11:32:03 AM IST) Answer:The least number to be subtracted from 86295031 is 145.Solution:Let us divide 86295031 by 582.86295031 (14873 582 _______ 2809 2328 _______ 4815 4656 _______ 1590 1164 _________ 4263 4074 __________ 1891 1746 ___________ 145 ____________ So the required number is 145. Like 11Dislike 7⚐ Report Related QuestionsNo related questions found for this page. |