Hey! The solution is as follows : Solubility of potassium nitrate at 313K = 62/100 100 g of water contains potassium nitrate = 62 g 50 g of water contains potassium nitrate = 62/100 X 50 = 31g Thus, 31 g potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 g of water at 313 K. Hope it helped to clear your delimma Thank you
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What mass of potassium chloride would be needed to form a saturated solution in 50 gram of water at 298 K?
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