What number should be added to each one of 6,14,18 and 38 to make them equally proportionate

What number should be added to each one of 6,14,18 and 38 to make them equally proportionate
What number should be added to each one of 6,14,18 and 38 to make them equally proportionate
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  1. What number should be added to each one of 6, 14, 18 and 38 to make them equally proportionate ?

Let the number be N,From question, (6 + N) / (14 + N) = (18 + N) / (38 + N) ⇒ (6 + N) x (38 + N ) = (18 + N ) x (14 + N )

⇒ N2 + 44N + 228 = N2 + 32N + 252

⇒ 12N = 24 ∴ N = 2

What number should be added to each one of 6,14,18 and 38 to make them equally proportionate


Correct Answer:

Description for Correct answer:

6, 14, 18, 38If a, b, c, d are in proportion=> a : b :: c : dthen ad = bcLet x is added in the sequence numbers as to make it in proportion(6+x) : (14+x) :: (18+x) : (38+x)(6+x) (38+x) = (18+x) (14+x)Now to save valuable time put value of x from options to make it proportion(6+x) (38+x) = (14+x) (18+x)=> \( \Large x^{2} + 44x + 228 = x^{2} + 32x + 252 \)12x => 252 - 22812x => 24

x => 2 Ans.


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