Text Solution Solution : The convex lenses and the plane mirror as shown in figure. <br> The combination behaves like a concave mirror. <br> Let the distance of the object from the first lens be x. <br> For the ray to retrace its path, it should be incident normally on the plane mirror. <br> Form the diagrm, we see that for lens `L_(2)` <br> `v=oo, f=+10cm, u=?` <br> Form the lens equation, we get <br> `(1)/(v)-(1)/(u)=(1)/(f)` or `u=-10cm` <br> From the diagram, we see that for lens `L_(1)` <br> `v=30-10=20cm, f=+10cm, u=-x` <br> From the lens equation, we get <br> `(1)/(v)-(1)/(u)=(1)/(f)` or `(1)/(20)-(1)/(-x)=(1)/(10)` or `x=20cm` <br> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/BMS_V04_C01_E01_119_S01.png" width="80%">
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Concept: Lens: The transparent curved surface which is used to refract the light and make an image of any object placed in front of it is called a lens. Convex lens: A lens having two spherical surfaces, bulging outwards is called a double convex lens (or simply convex lens).
The lens formula is: \(\frac{1}{{\rm{v}}} - \frac{1}{{\rm{u}}} = \frac{1}{{\rm{f}}}\) Magnification \(m = \frac v u\) Where, v = Distance of image, u = Distance of object, f = Focal length Calculation: Given: u = - 30 cm, f = 20 cm Using, \(\frac{1}{{\rm{v}}} - \frac{1}{{\rm{u}}} = \frac{1}{{\rm{f}}}\) \(\frac{1}{{\rm{v}}} - \frac{1}{{\rm{-30}}} = \frac{1}{{\rm{20}}}\) v = 60 cm Maginfication \(m = \frac v u\) \(m = \frac {60}{30}\) m = 2 Additional Information
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