When no more solute can be dissolved in solution at given temperature is called solution a homogeneous B heterogeneous C saturated D unsaturated?

  • UNSATURATED AND SATURATED SOLUTION

    Saturated solution

    Activity 2.2:

    *   Let us again divide the class into four groups – A, B, C, and D.

    *   Distribute the following samples to each group:

            -  Few crystals of copper sulphate to group A.

            -  One spatula full of copper sulphate to group B.

            -  Chalk powder or wheat flour to group C.

            -  Few drops of milk or ink to group D.

    *   Each group should add the given sample in water and stir properly using a glass rod. Are the particles in the mixture visible?

    *   Direct a beam of light from a torch through the beaker containing the mixture and observe from the front. Was the path of the beam of light visible?

    Leave the mixtures undisturbed for a few minutes (and set up the filtration apparatus in the meantime). Is the mixture stable or do the particles begin to settle after some time?

    *   Filter the mixture. Is there any residue on the filter paper?

    *   Discuss the results and form an opinion.

    *   Groups A and B have got a solution.

    *   Group C has got a suspension.

    *   Group D has got a colloidal solution.

    When no more solute can be dissolved in solution at given temperature is called solution a homogeneous B heterogeneous C saturated D unsaturated?

    Figure 2.1: Filtration

    In activity 2.2, we observed that groups A and B obtained different shades of solutions. So, we understand that in a solution the relative proportion of the solute and solvent can be varied. Depending upon the amount of solute present in a solution, it can be called a dilute, concentrated or a saturated solution. Dilute and concentrated are comparative terms. In activity 2.2, the solution obtained by group A is dilute as compared to that obtained by group B.

    What would happen if you were to take a saturated solution at a certain temperature and cool it slowly.

    Activity 2.3:

    *   Take approximately 50 mL of water each in two separate beakers.

    *   Add salt in one beaker and sugar or barium chloride in the second beaker with continuous stirring.

    *   When no more solute can be dissolved, heat the contents of the beaker to raise the temperature by about 5°C.

    *   Start adding the solute again.

    Is the amount of salt and sugar or barium chloride, that can be dissolved in water at a given temperature, the same?

    At any particular temperature, a solution that has dissolved as much solute as it is capable of dissolving, is said to be a saturated solution. In other words, when no more solute can be dissolved in a solution at a given temperature, it is called a saturated solution.

    Unsaturated solution

    If the amount of solute contained in a solution is less than the saturation level, it is called an unsaturated solution.

    Source: This topic is taken from NCERT TEXTBOOK

  • SOLUBILITY

    The amount of the solute present in the saturated solution at this temperature is called its solubility. We can infer from the above activity that different substances in a given solvent have different solubilities at the same temperature. The concentration of a solution is the amount (mass or volume) of solute present in a given amount (mass or volume) of solution.

    There are various ways of expressing the concentration of a solution, but here we will learn only three methods:

    i.    Mass by mass percentage

    ii.   Volume by volume percentage

    iii.  Mass by volume percentage

    Source: This topic is taken from NCERT TEXTBOOK

    1. If a compound is only slightly soluble in a particular solvent, what are the relative strengths of the solvent–solvent and solute–solute interactions versus the solute–solvent interactions?

    2. Predict whether each of the following sets of conditions favors formation of a solution:

    3. Arrange the following liquids in order of increasing solubility in water: t-butanol [(CH3)3COH], benzene, ammonia, and heptane. Justify your answer.

    4. Which compound in each pair will be more soluble in water? Explain your reasoning in each case.

      1. toluene (C7H8) or ethyl ether (C2H5OC2H5)
      2. chloroform (CHCl3) or acetone (CH3COCH3)
      3. carbon tetrachloride (CCl4) or tetrahydrofuran (C4H8O)
      4. CaCl2 or CH2Cl2

    5. Which compound in each pair will be more soluble in benzene? Explain your reasoning in each case.

      1. cyclohexane or methanol
      2. I2 or MgCl2
      3. methylene chloride (CH2Cl2) or acetic acid

    6. Two water-insoluble compounds—n-decylamine [CH3(CH2)9NH2] and n-decane—can be separated by the following procedure: The compounds are dissolved in a solvent such as toluene that is immiscible with water. When adding an aqueous HCl solution to the mixture and stirring vigorously, the HCl reacts with one of the compounds to produce a salt. When the stirring is stopped and the mixture is allowed to stand, two layers are formed. At this point, each layer contains only one of the two original compounds. After the layers are separated, adding aqueous NaOH to the aqueous layer liberates one of the original compounds, which can then be removed by stirring with a second portion of toluene to extract it from the water.

      1. Identify the compound that is present in each layer following the addition of HCl. Explain your reasoning.
      2. How can the original compounds be recovered from the toluene solution?

    7. Bromine and iodine are both soluble in CCl4, but bromine is much more soluble. Why?

    8. A solution is made by mixing 50.0 mL of liquid A with 75.0 mL of liquid B. Which is the solute, and which is the solvent? Is it valid to assume that the volume of the resulting solution will be 125 mL? Explain your answer.

    9. The compounds NaI, NaBr, and NaCl are far more soluble in water than NaF, a substance that is used to fluoridate drinking water. In fact, at 25°C the solubility of NaI is 184 g/100 mL of water, versus only 4.2 g/100 mL of water for NaF. Why is sodium iodide so much more soluble in water? Do you expect KCl to be more soluble or less soluble in water than NaCl?

    10. When water is mixed with a solvent with which it is immiscible, the two liquids usually form two separate layers. If the density of the nonaqueous solvent is 1.75 g/mL at room temperature, sketch the appearance of the heterogeneous mixture in a beaker and label which layer is which. If you were not sure of the density and the identity of the other liquid, how might you be able to identify which is the aqueous layer?

    11. When two liquids are immiscible, the addition of a third liquid can occasionally be used to induce the formation of a homogeneous solution containing all three.

      1. Ethylene glycol (HOCH2CH2OH) and hexane are immiscible, but adding acetone [(CH3)2CO] produces a homogeneous solution. Why does adding a third solvent produce a homogeneous solution?
      2. Methanol and n-hexane are immiscible. Which of the following solvents would you add to create a homogeneous solution—water, n-butanol, or cyclohexane? Justify your choice.

    12. Some proponents of vitamin therapy for combating illness encourage the consumption of large amounts of fat-soluble vitamins. Why can this be dangerous? Would it be as dangerous to consume large amounts of water-soluble vitamins? Why or why not?

    13. Why are most metals insoluble in virtually all solvents?

    14. Because sodium reacts violently with water, it is difficult to weigh out small quantities of sodium metal for a reaction due to its rapid reaction with small amounts of moisture in the air. Would a Na/Hg amalgam be as sensitive to moisture as metallic sodium? Why or why not? A Na/K alloy is a liquid at room temperature. Will it be more or less sensitive to moisture than solid Na or K?

    15. Dental amalgams often contain high concentrations of Hg, which is highly toxic. Why isn’t dental amalgam toxic?

    16. Arrange 2,2,3-trimethylpentane, 1-propanol, toluene (C7H8), and dimethyl sulfoxide [(CH3)2S=O] in order of increasing dipole moment. Explain your reasoning.

    17. Arrange acetone, chloroform, cyclohexane, and 2-butanol in order of increasing dielectric constant. Explain your reasoning.

    18. Dissolving a white crystalline compound in ethanol gave a blue solution. Evaporating the ethanol from the solution gave a bluish-crystalline product, which slowly transformed into the original white solid on standing in the air for several days. Explain what happened. How does the mass of the initial bluish solid compare with the mass of the white solid finally recovered?

    19. You have been asked to develop a new drug that could be used to bind Fe3+ ions in patients who suffer from iron toxicity, allowing the bound iron to be excreted in the urine. Would you consider a crown ether or a cryptand to be a reasonable candidate for such a drug? Explain your answer.

    20. Describe two different situations in which fractional crystallization will not work as a separation technique when attempting to isolate a single compound from a mixture.

    21. You have been given a mixture of two compounds—A and B—and have been told to isolate pure A. You know that pure A has a lower solubility than pure B and that the solubilities of both A and B increase with temperature. Outline a procedure to isolate pure A. If B had the lower solubility, could you use the same procedure to isolate pure A? Why or why not?