You put 1 kg of ice at 0 c together with 1 kg of water at 50 c what is the final temperature

Text Solution

`40^(@)C``60^(@)C``0^(@)C``50^(@)C`

Answer : C

Solution : heat given out due to cooling of water from `80^(@)C` to `0^(@)C=H_(1)=msDeltat=1xx4200xx(80-0)` <br> `=336000J=336kJ`. <br> Heat required for the melting of ice from and at <br> `0^(@)C=H_(2)=mL=1xx336kJ`. <br> Since `H_(1)=H_(2)`, the final temperature of the mixture will be `0^(@)C` and it will be totally water.

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