In what time would a 360m long train move at the speed of 44 km HR will cross a 140 m long bridge?

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• Question
• 
  Options
• A. 36 sec
• B. 39 sec
• C. 41 sec
• D. 43 sec


• Correct Answer
• 41 sec 

  Explanation

  
  

  Speed = 44 kmph x 5/18 = 110/9 m/s

  We know that, Time = distance/speed

  Time = (360 + 140) / (110/9)

  = 500 x 9/110 = 41 sec.

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• 1. A bus covers its journey at the speed of 80km/hr in 10hours. If the same distance is to be covered in 4 hours, by how much the speed of bus will have to increase ?
• 
  Options
• A. 85 km/hr
• B. 95 km/hr
• C. 105 km/hr
• D. 120 km/hr
Discuss


Correct Answer: 120 km/hr

Explanation:

Initial speed = 80km/hrTotal distance = 80 x 10 = 800kmNew speed = 800/4 =200km/hr

Increase in speed = 200 - 80 = 120km/hr

• 2. A man whose speed is 4.5 kmph in still water rows to a certain upstream point and back to the starting point in a river which flows at 1.5 kmph, find his average speed for the total journey ?
• 
  Options
• A. 5 kmph
• B. 7 kmph
• C. 3 kmph
• D. 4 kmph
Discuss


Correct Answer: 4 kmph

Explanation:

Speed of Man = 4.5 kmphSpeed of stream = 1.5 kmphSpeed in DownStream = 6 kmphSpeed in UpStream = 3 kmph

Average Speed = (2 x 6 x 3)/9 = 4 kmph.

• 3. A person takes 20 minutes more to cover a certain distance by decreasing his speed by 20%. What is the time taken to cover the distance at his original speed ?
• 
  Options
• A. 1hr
• B. 1 hr 20 min
• C. 1 hr 10 min
• D. 50 min
Discuss


Correct Answer: 1 hr 20 min

Explanation:

Let the distance and original speed be 'd' km and 'k' kmph respectively.

d/0.8k - d/k = 20/60 => 5d/4k - d/k = 1/3

=> (5d - 4d)/4k = 1/3 => d = 4/3 k

Time taken to cover the distance at original speed

= d/k = 4/3 hours = 1 hour 20 minutes.

• 4. Three friends Rudra, Siva and Anvesh start to run around a circular stadium. They complete a revolution in 24, 36 and 30 seconds respectively. After how many minutes will they meet at the starting point ?
• 
  Options
• A. 60
• B. 120
• C. 360
• D. 6
Discuss


Correct Answer: 6

Explanation:

For this we have to find the LCM of 24, 36 and 30

LCM of 24, 36 and 30 = 360 sec

360/60 min = 6 minutes.

• 5. Chennai express left Hyderabad for Chennai at 14 : 30 hours, travelling at a speed of 60 kmph and Charminar Express left Hyderabad for Chennai on the same day at 16 : 30 hours, travelling at a speed of 80 kmph. How far away from Hyderabad will the two trains meet?
• 
  Options
• A. 360 kms
• B. 480 kms
• C. 520 kms
• D. 240 kms
Discuss


Correct Answer: 480 kms

Explanation:

Now, the distance covered by Chennai express in 2 hrs = 60 x 2 = 120 kms

Let the Charminar Express takes 't' hrs to catch Chennai express

=> 80 x t = 60 x (2 + t)

=> 80 t = 120 + 60t

=> t = 6 hrs

Therefore, the distance away from Hyderabad the two trains meet = 80 x 6 = 480 kms.

• 6. K and L starts walking towards each other at 4 pm at speed of 3 km/hr and 4 km/hr respectively. They were initially 17.5 km apart. At what time do they meet ?
• 
  Options
• A. 6:00 am
• B. 6:30 pm
• C. 5:45 am
• D. 5:52 pm
Discuss


Correct Answer: 6:30 pm

Explanation:

Suppose they meet after 'h' hours

Then

3h + 4h = 17.5

7h = 17.5

h = 2.5 hours

So they meet at => 4 + 2.5 = 6:30 pm

• 7. Mr. Karthik drives to work at an average speed of 48 km/hr. Time taken to cover the first 60% of the distance is 20 minutes more than the time taken to cover the remaining distance. Then how far is his office ?
• 
  Options
• A. 40 km
• B. 50 km
• C. 70 km
• D. 80 km
Discuss


Correct Answer: 80 km

Explanation:

Let the total distance be 'x' km.

Time taken to cover remaining 40% of x distance is    t 1 = 40 � x 100 � 48


But given time taken to cover first 60% of x distance is    t 2 = t 1 + 20 60 h r s

  t 2 = 60 � x 100 � 48

? 60 � x 100 � 48 =   40 � x 100 � 48 + 20 60

 x=80 km.

• 8. A man covered a certain distance at some speed. Had he moved 3 kmph faster, he would have taken 40 minutes less. If he had moved 2 kmph slower, he would have taken 40 minutes more. The distance (in km) is
• 
  Options
• A. 30
• B. 36
• C. 40
• D. 42
Discuss


Correct Answer: 40

Explanation:

Let distance = x km and usual rate = y kmph.Then, x/y - x/(y+3) = 40/60 --> 2y (y+3) = 9x ----- (i)Also, x/(y-2) - x/y = 40/60 --> y(y-2) = 3x -------- (ii)

On dividing (i) by (ii), we get:

x = 40 km.

• 9. Buses start from a bus terminal with a speed of 20 km/hr at intervals of 10 minutes. What is the speed of a man coming from the opposite direction towards the bus terminal if he meets the buses at intervals of 8 minutes?
• 
  Options
• A. 5 kmph
• B. 6 kmph
• C. 7.5 kmph
• D. 8 kmph
Discuss


Correct Answer: 5 kmph

Explanation:

Let p be the speed of man in kmph

According to the given data in the question,

Distance travelled by bus in 10 min with 20 kmph == Distance travelled by man in 8 min with (20 + p) kmph in opposite direction

=> 20 x 10/60 = 8/60 (20 + p)

=> 200 = 160 + 8p

=> p = 40/8 = 5 kmph.

• 10. The ratio of the speeds of a car, a jeeps and a tractor is 3 : 5 : 2. The speed of the jeep is 250 per cent of the speed of the tractor and tractor covers 360 km in 12 hours. What is the average speed of car and jeep together?
• 
  Options
• A. 50 kmph
• B. 60 kmph
• C. 70 kmph
• D. 80 kmph
Discuss


Correct Answer: 60 kmph

Explanation:

Speed of tractor = 360/12 = 30 kmph

Speed of jeep = 250 x 30/100 = 75 kmph

But, given ratio of speed of car, jeep and tractor is 3 : 5 : 2

Speed of car = 3 x 75/5 = 45 kmph

Required, average speed of car and jeep = 75 + 45/2 = 60 kmph.

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