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Tags: Class 11 , Physics , Laws of Motion Asked by Vagmita Pandya
Open in App Suggest Corrections 1 Text Solution Solution : Here, ` y = ut + (1)/(2) g t^(2) ` <br> ` velocity , upsilon = (dy)/(dt)=u+ (1)/(2) g (2t)= u + g t , ` <br> acceleration `a = (du)/(dt) = 0 + g = g ` <br> ` As F= ma :. F = mg ` <br> Thus the given equation describes the motion of a partical under acceleration due to gravity , and y is the position co- ordinate in the direction of g . |