What is the probability of getting a number less than 5 when a die is thrown once?

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting a number less than 5.

   Then, the favourable outcomes are 1, 2, 3, 4

   Number of favourable outcomes = 4

∴ Probability of getting a number less than 5 =  P (E) = `"Number of favourable outcome"/"Total number of possible outcomes"=4/6 = 2/3`

Page 2

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting a number greater than 2.

Then, the favourable outcomes are 3, 4, 5 and 6.

Number of favourable outcomes = 4

∴ Probability of getting a number greater than 2 =  P (E) =`"Number of favourable outcomes"/"Total number of possible outcomes" = 4/6 = 2/3` 

Page 3

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting a number between 3 and 6.

Then, the favourable outcomes are 4, 5

Number of favourable outcomes = 2

∴ Probability of getting a number between 3 and 6 =  P (E)= `"Number of favourable outcomes "/"Total number of possible outcomes" = 2/6 = 1/3`

Page 4

A die is thrown once. Find the probability of getting a number other than 3.

 Let E be the event of getting a number other than 3.  

   Then, the favourable outcomes are 1, 2, 4, 5 and 6.     

    Number of favourable outcomes = 5
∴ Probability of getting a number other than 3 =  P (E) = `"Number of favourable outcomes"/"Total number of possible outcomes" = 5/6`

Concept: Concept Or Properties of Probability

  Is there an error in this question or solution?

Page 5

In a single throw of a die, the possible outcomes are 1, 2, 3, 4, 5 and 6.

Total number of possible outcomes = 6

Let E be the event of getting the number 5.

Then, the favourable outcome is 5.

Number of favourable outcomes = 1

∴ Probability of getting the number 5 =  P (E) = `"Number of favourable outcome"/"Total number of possible outcomes" =1/6`

Solution:

When a die is thrown, the possible outcomes are 1,2,3,4,5,6.

Number of possible outcomes = 6

(i) Let E be the event of getting an odd number.

Outcomes favourable to E are 1,3,5.

Number of favourable outcomes = 3

P(E) = 3/6 = ½

Hence the probability of getting an odd number is ½.

(ii)Let E be event of getting a number less than 5.

Outcomes favourable to E are 1,2,3,4

Number of favourable outcomes = 4

P(E) = 4/6 = 2/3

Hence the probability of getting a number less than 5 is 2/3.

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