What is the strength of the electric field in a region where the electric potential is constant?

The electric field strength is the force experienced on the charge. This article discusses whether the electric field strength is constant throughout the field or is variable.

The electric field strength is constant in the uniform electric field. It depends upon the total number of charges and the distance between them. The electric field strength varies with the distance between the charge and the introduction of new point charges in the field; otherwise, it is constant.

The electric field strength does not depend on the drift velocity of charges. The potential differences have to be constant for the constant electric field strength. We shall further discuss the conditions and facts for the constant electric field in this topic.

When is electric field strength constant?

The intensity of the field generated by the charged particle is the strength of its electric field. Let us discuss when this electric field strength is constant.

The electric field strength is constant only when the rate of change of electric potential with distance is constant, and there is no variation in the total amount of charge present in that field. The electric flux density flowing through the area/electric field region is constant throughout.

How is electric field strength constant?

The electric field strength is a ratio of potential difference and the distance between the two charges/ surfaces. Let us see how the electric field strength can be constant.

The electric field strength is constant if the electric potential between the charges/ charged plates and the distance between both is invariable and constant. The potential difference between any two points in the electric field is zero if the electric field strength is constant.

Moreover, the electric field strength is constant if the force experienced on the unit charge particle present in the field is constant throughout the electric field region. The electric flux density in such a field also remains constant.

Does electric field depend on voltage?

The voltage at a point in the electric field is most vital to creating the electric field. Let us elaborately discuss the electric field dependency on voltage.

The electric field depends on the voltage and is directly proportional to the potential difference across the two charged points because it is responsible for building the electric field in that region. The voltage is the product of the electric field and the distance between the charges/ charged plates.

The electric field between the capacitor plates is due to the voltage difference across the oppositely charged plates. The formula gives the relation between the electric field and the voltage: E = V/d, where E is the electric field, V is a voltage, and d is the distance between the two charges.

Is electric field strength always constant?

The electric field strength is constant if the potential difference across the points is constant. Let us discuss whether the electric field strength is always constant or not.

The electric field strength is not always constant because it varies with an uneven potential difference at any point in the field. It also varies with the mobility of the charged particles in the field, unsteady electric force, the flux lines penetrating through the region, and the current flow.

The electric field strength also varies at the square rate of a distance between the two charges. The electric field strength will change if the distance between the charges also varies.

Is electric field strength constant between two plates?

The potential difference between the two charged plates generates the electric field. Let us clarify whether the electric field strength is constant between two plates.

The electric field strength between the two plates is constant because the total numbers of charges on the two plates have oppositely charged, and the area of the plates remains constant. If the plate size is tiny, then the distance between the two plates does not matter.

The formula gives the electric field between the two plates: E = Q/(Ae0); here, E is the electric field, Q is a total charge on the plates, A is the area of the plates, and e0 is the permeability of the free space.

Is the strength of an electric field the same everywhere?

An electric field’s strength depends upon the number of electric fluxes. Let us briefly discuss whether the strength of an electric field is the same everywhere.

The electric field strength of an electric field is the same everywhere in the uniform electric field because the electric flux passing through the unit area of the field is the same, and the potential difference at any two points in the field is constant. 

Conclusion

We can conclude with this article that the electric field strength is constant in the uniform field. The electric field strength depends upon the charge, potential difference, and distance between the two charges and varies with the variable electric flux and the drift velocity of the charges.

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It is an interesting question:

Firstly, the Electric field "$E$" is the slope of the potential, i.e., $E=-{\frac{dV}{dx}}$. Therefore "constant electric field" means the potential is either increasing or decreasing at a constant rate (along the space).

Secondly, $E$ is a physically measurable quantity but $V$ is not. You can never know the absolute value of potential $V$, although you know the value of $E$ which is constant in your case. It is because,

$V=-\int Edx$ $=$$-Ex+C$

Note that we have an integrating constant "$C$", i.e., you can always add any constant value with your solution for the potential. It further means $V$ must be measured with respect to some reference and the measured value always depends on that reference.

An example: Let's consider a parallel plate capacitor in which Potential of one plate is $V_1$ and another plate is $V_2$ and they are located at position $x_1$ and $x_2$ respectively. Also let the distance between two plates, $dx=x_2-x_1$=2cm, and electric field (which is ideally constant in such capacitor) $E=5V/cm$.

What is the value of potential that satisfies the case? Lets check,

if $V_1=0V$ and $V_2=10V$ then $E={\frac{dV}{dx}}={\frac{V_2-V_1}{dx}}={\frac{10-0}{2}}=5V/cm$

Now lets add some constant value with the potentials. i.e.,

if $V_1=5V$ and $V_2=15V$ then $E={\frac{V_2-V_1}{dx}}={\frac{15-5}{2}}=5V/cm$

if $V_1=10V$ and $V_2=20V$ then $E={\frac{V_2-V_1}{dx}}={\frac{20-10}{2}}=5V/cm$

See!!!! All of those set of ($V_1$,$V_2$) is giving the same "Constant" electric field. Therefore you can know the potential of one plate with respect to the potential of another, but can never know the absolute value of both.

This is true not only for capacitor but also for every other cases. At this point the potential of "Earth" is usually taken to be the reference in order to measure the potential at any point. It is because earth is a very large object and it's absolute potential does not get affected by any of our action.