When the kinetic energy of the body is increased by 300 %` The momentum of the body is increased by in %)?

Text Solution

100 %15 %`sqrt300%`17.5 %

Answer : A

Solution : Let initial kinetic energy, `E_(1)=E` <br> Final kinetic energy, `E_(2)=E+300%` of E = 4E <br> As `P prop sqrt(E ) rArr (P_(2))/(P_(1))=sqrt((E_(2))/(E_(1)))=sqrt((4E)/(E ))=2 rArr P_(2)=2P_(1)` <br> `rArr P_(2)=P_(1)+100 %` of `P_(1)` <br> i.e. Momentum will increase by 100%.