At a constant temperature what should be the percentage increase in pressure for a 5% decrease

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Let initial volume and pressure be $V_{1}$ and $P_{1}$ respectively.
Let final volume and pressure be $V_{2}$ and $P_{2}$ .
Using $P V = n RT$ , if temperature is constant, then $P V =$ constant.
$\Rightarrow P_{1} V_{1} = P_{2} V_{2}$
Given, final volume is $95%$ of initial volume.
$\Rightarrow V_{2} = \frac{95 V _{1}}{100}$
$\Rightarrow P_{1} V_{1} = P_{2} \times \frac{95 V _{1}}{100}$
$\Rightarrow P_{1} = P_{2} \times \frac{95}{100}$
$\Rightarrow P_{2} = P_{1} \times \frac{100}{95} = 1.052631 P_{1}$ .
This roughly translates to an increase of $5.2631%$ .
Therefore the pressure should be increased by $5.2631%$ approximately.