As the distance between two bodies increases the intensity of gravitational force decreases by a factor of 1/r2, where r = distance between two bodies. The whole business of gravitational force was first put forward by great scientist Sir Isaac Newton. According to his Law of gravitation, the force acting between two bodies is given by F = m1m2/r2 where m1 = mass of object 1 m2 = mass of object 2
Option 3 : The force would be halved
10 Questions 10 Marks 10 Mins
CONCEPT:
\(\Rightarrow F \propto \frac{M_1M_2}{R^2} \Rightarrow F = \frac {GM_1M_2}{R^2} \) Where G = 6.674 × 10-11 m3Kg-1s-2 is a universal constant
CALCULATION: Given: Mass of the one body (M1) = M, Mass of the another body (M2) = 2M, initial distance = R, Final distance = 2R,F = Initial Force, F' = Final force M1 = M, M2 = 2M, R' = 2R \(\Rightarrow F \propto \frac{M_1M_2}{R^2}\) \(F'=\frac{GM_1M_2}{R'^2} =\frac{G M_1(2M_2)}{(2R)^2}=\frac {2GM_1M_2}{4R^2}=\frac {1}{2}F\) Hence, the Force would be halved is the correct answer. India’s #1 Learning Platform Start Complete Exam Preparation
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