What is the current in a toaster If the toaster uses 1500 W of power when plugged into a 110 V wall outlet?

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An 1800-W toaster, a 1400-W electric frying pan, and a 75-W lamp are plugged into the same outlet in a 15-A, 120-V circuit. (The three devices are in parallel when plugged into the same socket.). (a) What current is drawn by each device? (b) Will this combination blow the 15-A fuse?

$I_\textrm{toaster} = 15\textrm{ A}$, $I_\textrm{frying pan} = 11.7\textrm{ A}$, $I_\textrm{lamp} = 0.63\textrm{ A}$
$I > 15\textrm{ A}$, therefore yes, the combination will blow the 15 amp fuse.

This is College Physics Answers with Shaun Dychko. We have three appliances connected in parallel to a 120 volt outlet and the first appliance is a toaster drawing 1800 watts and we have a frying pan drawing 1400 watts and a lamp drawing 75 watts and the question is what is the current going through each device assuming that the fuse hasn't blown yet? So in part (a), we can see that power is current times voltage and we can solve for the current I by dividing both sides by V so the current then is power divided by voltage. And so we take each power for each device and divide them by 120 volts because they all experience the same voltage since they are connected in parallel to this regular North American outlet. So for the toaster we have 1800 watts divided by 120 volts that is 15 amps; the frying pan is 1400 watts divided by 120 volts which is 11.7 amps; and the lamp will draw 0.63 amps. Kirchhoff's junction rule says that the total current drawn through the circuit breaker that goes into this junction is going to equal the total current going out of the junction and we just figured out the three currents going out of the junction— the toaster current, the frying pan current and the lamp current— and so Kirchhoff's junction rule says that these three currents going out have to equal the current going in and this current going in is the current that will be through the fuse so that's 15 amps plus 11.7 amps plus 0.63 amps which is 27 amps. Now since that exceeds the 15 amp limit of this particular fuse, this combination will blow the 15 amp fuse.

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Please provide any 2 values and click "Calculate" to get the other values in the ohm's law equations V = I × R and P = V × I.

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Ohm's Law

Ohm's Law states that the current through a conductor between two points is directly proportional to the voltage. This is true for many materials, over a wide range of voltages and currents, and the resistance and conductance of electronic components made from these materials remain constant. Ohm's Law is true for circuits that contain only resistive elements (no capacitors or inductors), regardless of whether the driving voltage or current is constant (DC) or time-varying (AC). It can be expressed using a number of equations, usually all three together, as shown below.

Where:

V is voltage in Volts R is resistance in Ohms

I is current in Amperes

Electrical Power

Power is the rate at which electrical energy is transferred by an electric circuit per unit time typically expressed in the SI (International System of Units) unit of Watts. Power is typically produced by electric generators and supplied to businesses and homes through the electric power industry, but can also be supplied by electric batteries or other sources.

In resistive circuits, Joule's Law can be combined with Ohm's Law to produce alternative expressions for the amount of power dissipated, as shown below.

P = V × I
P =
P = I2 × R

Where:

P is power in Watts

Ohm's Law Formula Wheel

Below is a formula wheel for Ohm's Law relationships between P, I, V, and R. This is essentially what the calculator does, and is just a representation of the algebraic manipulation of the equations above. To use the wheel, choose the variable to solve for in the middle of the wheel, then use the relationship for the two known variables within the cross section of the circle.

A toaster is found in most kitchens and is a popular home appliance for toasting bread or heating up certain pre-baked toaster pastries. The bread toaster uses from 800 to 1500 watts of energy when in use, an average toaster will use around 1200 watts.

Click calculate to find the energy consumption of a bread toaster using 1200 Watts for 0.20 hours a day @ $0.10 per kWh. This equals to toasting 6 slices of bread for 12 minutes in total each day.

Hours Used Per Day: Enter how many hours the device is being used on average per day, if the power consumption is lower than 1 hour per day enter as a decimal. (For example: 30 minutes per day is 0.5)

Power Use (Watts): Enter the average power consumption of the device in watts.

Price (kWh): Enter the cost you are paying on average per kilowatt hour, our caculators use the default value of 0.10 or 10 cents. To find an exact price check your electricity bill or take a look at Global Electricity Prices.

The bread toaster is the quickest and most effective device to toast bread, not much energy can be saved with a bread toaster. Most bread toasters are mechanical and use almost no standby or idle power. Avoid toasting bread in the oven or stove as they are less efficient and will use considerably more energy.