When the length of shadow of a vertical pole is equal to √ times of its height the angle of elevation of the suns altitude is a 150 B 300 C 450 D 600?

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Formula used:

tanθ = Perpendicular/Base

tan60° = √3

Calculation:

Let AB be the pole and BC be its shadow.

Let the length of shadow be x and the length of the pole be √3x.

Now, in ΔABC, let θ be the angle of elevation of the sun

⇒ tanθ = AB/BC

⇒ tanθ = √3x/x = √3

⇒ θ = 60°

∴ The angle of elevation of the sun at the time of shadow is 60°.

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If the height of a vertical pole is √3 times the length of its shadow on the ground then the angle of elevation of the sun at that time is a 30∘ b 45∘ c 60∘ d 75∘

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